Question

A body of mass 10 kg is initially at a height of 20 m above the ground. It falls to a height of 5 m above the ground. Its potential energy in the new position is​

Answer 1

Explanation:

Given:

• Mass of the body = 10 kg
• Initially at a height = 20 m
• It falls to a height = 5 m

To find:

• The PE in the new position = ?

Solution:

We know, Potential energy (PE) = mass (m) × acc. due to gravity (g) × height (h)

The body was at a height of 20 m and then falls to a height of 5 m. We've to find the PE in new position.

Total height (h) = 20 - 5

= 15 meters

(put the values in the formula)...

$= = > \: potential \: energy \: = \: 10 \: \times \: 10 \: \times \: 15$

$= = > \: PE \: = \: 1500 \: Joules$

Hence, the potential energy in new position is 1500 J.

Hope it helped you dear...

Answer 2

Given info : A body of mass 10 kg is initially at a height of 20 m above the ground. It falls to a height of 5 m above the ground.

To find : the potential energy in the new position is ..

solution : potential energy of a body depends on height of the body from the ground. it is given by, U = mgh, where g is acceleration due to gravity, m is mass of the body and h is the height of the body from the ground.

here, initial height of the body, h₀ = 20 m

final height of the body, h₁ = h₀ - 5 m = 20m - 5 m = 15 m

now the potential energy of the body, U = mgh₁

here, m = 10 kg , g = 10 m/s² and h₁ = 15 m

∴ U = 10 × 10 × 15 = 1500 J

therefore the potential energy in the new position is 1500 J.