A body of mass 10 kg is initially at a height of 20 m above the ground. It falls to a height of 5 m above the ground. Its potential energy in the new position is
Answers
Explanation:
Given:
- Mass of the body = 10 kg
- Initially at a height = 20 m
- It falls to a height = 5 m
To find:
- The PE in the new position = ?
Solution:
We know, Potential energy (PE) = mass (m) × acc. due to gravity (g) × height (h)
The body was at a height of 20 m and then falls to a height of 5 m. We've to find the PE in new position.
Total height (h) = 20 - 5
= 15 meters
(put the values in the formula)...
Hence, the potential energy in new position is 1500 J.
Hope it helped you dear...
Given info : A body of mass 10 kg is initially at a height of 20 m above the ground. It falls to a height of 5 m above the ground.
To find : the potential energy in the new position is ..
solution : potential energy of a body depends on height of the body from the ground. it is given by, U = mgh, where g is acceleration due to gravity, m is mass of the body and h is the height of the body from the ground.
here, initial height of the body, h₀ = 20 m
final height of the body, h₁ = h₀ - 5 m = 20m - 5 m = 15 m
now the potential energy of the body, U = mgh₁
here, m = 10 kg , g = 10 m/s² and h₁ = 15 m
∴ U = 10 × 10 × 15 = 1500 J
therefore the potential energy in the new position is 1500 J.