Physics, asked by ilmarangrez29, 17 days ago

A body of mass 10 kg is initially at a height of 20 m above the ground. It falls to a height of 5 m above the ground. Its potential energy in the new position is:
490
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100​

Answers

Answered by veeramallakirankumar
1

Answer:

Given:

Mass of the body = 10 kg

Initially at a height = 20 m

It falls to a height = 5 m

To find:

The PE in the new position = ?

Solution:

We know, Potential energy (PE) = mass (m) × acc. due to gravity (g) × height (h)

The body was at a height of 20 m and then falls to a height of 5 m. We've to find the PE in new position.

Total height (h) = 20 - 5

= 15 meters

(put the values in the formula)...

= = > \: potential \: energy \: = \: 10 \: \times \: 10 \: \times \: 15==>potentialenergy=10×10×15

= = > \: PE \: = \: 1500 \: Joules==>PE=1500Joules

Hence, the potential energy in new position is 1500 J.

Answered by kani082005
8

Answer:

490 J

refer to the image for explanation

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