A body of mass 10 kg is initially at a height of 20 m above the ground. It falls to a height of 5 m above the ground. Its potential energy in the new position is:
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Answer:
Given:
Mass of the body = 10 kg
Initially at a height = 20 m
It falls to a height = 5 m
To find:
The PE in the new position = ?
Solution:
We know, Potential energy (PE) = mass (m) × acc. due to gravity (g) × height (h)
The body was at a height of 20 m and then falls to a height of 5 m. We've to find the PE in new position.
Total height (h) = 20 - 5
= 15 meters
(put the values in the formula)...
= = > \: potential \: energy \: = \: 10 \: \times \: 10 \: \times \: 15==>potentialenergy=10×10×15
= = > \: PE \: = \: 1500 \: Joules==>PE=1500Joules
Hence, the potential energy in new position is 1500 J.
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Answer:
490 J
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