a body of mass 10 kg is kept at rest on frictionless surface surface it is set into motion when a force of 15 newton is applied on it calculate the work done by the force in 10 seconds so that the work done is equal to the change in ke of the body
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F=15 N
Mass=10 Kg
Acceleration due to F = 15/10=3/2 m/s^2
after 10 seconds.. distance covered=
S=ut+1/2at^2
= 0+ 1/2×3/2/100=75m
Work = F.S = 750 Joules
Mass=10 Kg
Acceleration due to F = 15/10=3/2 m/s^2
after 10 seconds.. distance covered=
S=ut+1/2at^2
= 0+ 1/2×3/2/100=75m
Work = F.S = 750 Joules
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