A body of mass 10 kg is moved on a rough horizontal surface at uniform speed of 5ms-1. the coefficient of friction between the body and the surface is 0.2,then the work done on 1s is
Answers
Answered by
0
Answer:
Mass M=10kg
Work done, W=150J
Displcement on horizontal = displacement on incline =d=2m
Friction force on horizontal plane,F
r
=μmg
Friction force on incline plane,F
r
′
=μmgcosθ
Speed is uniform means net acting force is equal to friction force
Work done,W=F
r
.d=μmg.d
⇒μ=
mg.d
W =
10×10×2150=0.75
Work done on incline plane, W=F r
′d=μmgcosθ.d
⇒W=0.75×10×10×cos30o ×2
⇒W=753J
Work done against friction is 753J
Similar questions