A body of mass 10 kg is moving eastward with a uniform speed of 2m/s.a force of 20 n is applied to it towards north.what is the magnitude of displacement after two sec.
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it is simple
Power=F×v
=20×2=40W
so now displacement S
P=(F×S)/t
40=20×S/2
S=4 m
so the displacement is 4 metres
Power=F×v
=20×2=40W
so now displacement S
P=(F×S)/t
40=20×S/2
S=4 m
so the displacement is 4 metres
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