A body of mass 10 kg is
moving on a a circular
track of radius 15 m.
What is work done on
it in one complete
revolution?
(Take
g= 10 ms-3)
Answers
heya~
Work done W=FScosθ
Work done W=FScosθwhere θ is the angle between F and S.
Work done W=FScosθwhere θ is the angle between F and S.If θ=90
Work done W=FScosθwhere θ is the angle between F and S.If θ=90 o
Work done W=FScosθwhere θ is the angle between F and S.If θ=90 o ⟹W=0
Work done W=FScosθwhere θ is the angle between F and S.If θ=90 o ⟹W=0Thus the work done by a force will be zero if the object moves in a direction perpendicular to the direction of applied force.
Work done W=FScosθwhere θ is the angle between F and S.If θ=90 o ⟹W=0Thus the work done by a force will be zero if the object moves in a direction perpendicular to the direction of applied force.Displacement of the body revolving in a circular path is along the tangent whereas centripetal force acts radially inwards i.e they are perpendicular to each other.
Work done W=FScosθwhere θ is the angle between F and S.If θ=90 o ⟹W=0Thus the work done by a force will be zero if the object moves in a direction perpendicular to the direction of applied force.Displacement of the body revolving in a circular path is along the tangent whereas centripetal force acts radially inwards i.e they are perpendicular to each other.Hence, work done in this case by the centripetal force is zero.