A body of mass 10 kg is moving on an inclined plane of inclination 30° with an acceleration 2 m/s^2 by applying a constant force F as shown in the figure. Take(g=10m/sec^2). Find the work done on the block by applied force F in 2s is
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v = u + at
= 0 + 2×2
= 4 m/s
F = ma
= 10× 4 /2
= 10 N
= 0 + 2×2
= 4 m/s
F = ma
= 10× 4 /2
= 10 N
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