Question

A body of mass 10 kg is moving with a constant velocity of 10 m/s. When a constant force acts for 4 sec
on it, it moves with a velocity 2 m/sec in the opposite direction. The acceleration produced in it is​

Answer 1

Answer:

a =-3 m/sec2 is answer by 1st eqution of motion

Answer 2

Answer:

F = m(v-u)÷t

or, F = 10(2-(-10))÷4 N

or,F = 10×12÷4 N

or, F = 30 N

or, ma = 30 N

or, a = 30÷10 = 3m/s^2(Answer)

Explanation:

This is the best way if you want to find the force also. Please mark it as BRAINLIEST.