Question

a body of mass 10 kg is moving with a velocity 10m/s. when a force is applied unit, after 25 sec is velocity become 30m/s . find the magnititude applied​

Answer 1

⇝ Appropriate Question :-

A body of mass 10 kg is moving with a velocity 10 m/s. When a force is applied on it, after 25 sec its velocity become 30 m/s . Find the magnititude of Force applied.

⇝ Given :-

• A body of mass 10 kg is moving with a velocity 10 m/s.

• When a force is applied on it for 25 sec its velocity become 30 m/s.

⇝ To Find :-

• Magnitude of Force applied.

⇝ Solution :-

Here,

• Initial Velocity = u = 10 m/s

• Final Velocity = v = 30 m/s

• Time = t = 25 s

Let Acceleration of Body be = a m/s²

❒ We Have 1st Equation of Motion as :

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{v = u + at}}}$

✧ Putting Values In 1st Equation of Motion ;

$:\longmapsto \rm 30 = 10 + a \times 25$

$:\longmapsto \rm 25a = 30 - 10$

$:\longmapsto \rm 25a = 20$

$:\longmapsto \rm a = \frac{20}{25}$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf a = 0.8\:m/s²} }}}$

❒ As We Know that :

$\large \bf \red\bigstar \: \: \orange{ \underbrace{ \underline{F= ma}}}$

✧ Putting Values In Above Formula ;

$:\longmapsto \rm Force \: Applied = 10 \times 0.8$

$\purple{ \large :\longmapsto  \underline {\boxed{{\bf Force Applied = 8N} }}}$

Therefore,

$\large\underline{\pink{\underline{\frak{\pmb{Magnitude\: of \:Force \: \text Applied = 8 \text N}}}}}$

Answer 2

Answer:

8N

Explanation:

We have,

Mass = 10kg

Initial velocity = 10m/s

Final velocity = 30m/s

Finding acceleration(a m/s^2)

We know that,

v = u + at (First eq. of motion)

On putting values in the formula,we get,

=> 30 = 10 + a × 25

=> 25a = 30 - 10.

=> 25a = 20

=> a = 20/25

=> a = 0.8m/s^2

Calculating magnitude of force applied

Formula Required to calculate magnitude of force applied

F = ma

On putting values in the formula, we get,

=> F = 10 × 0.8

=> F = 8.0

=> F = 8N

∴ Magnitude of force applied is 8N