Question

A body of mass 10 kg is moving with a velocity 20 m/s if the mass of the body is doubled and it's velocity is halved find its initial kinetic energy and final kinetic energy

Answer 1

Answer:

The initial kinetic energy is 2000 J and the final kinetic energy is 1000 J.

Explanation:

Given that,

Mass of body m = 10 kg

Initial  velocity $v = 20 m/s$

Final velocity $v = 10 \ m/s$

We know that,

The kinetic energy is defined as:

$K.E = \dfrac{1}{2}mv^2$

Here, m = mass of the body

v = velocity

The initial kinetic energy

$K.E = \dfrac{1}{2}m_{1}v_{1}^2$

Here, v = initial velocity

$K.E=\dfrac{1}{2}\times10\times20\times20$

$K.E_{i}= 2000\ J$

If the mass of the body is doubled and it's velocity is halved.

The final kinetic energy is

$K.E = \dfrac{1}{2}m_{2}v_{2}^2$

Here, v = final velocity

$K.E=\dfrac{1}{2}\times20\times10\times10$

$K.E_{i}= 1000\ J$

Hence, The initial kinetic energy is 2000 J and the final kinetic energy is 1000 J.

Answer 2

Explanation:

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