Question

A body of mass 10 kg is moving with a velocity of 1 m/s. find the magnitude of the force required to stop the body in 10 seconds and the distance the body will move through before coming to rest

Answer 1

u = 1 m/s
v = 0 m/s (As the body comes to rest)
t = 10 seconds

So, a = (v - u)/t
So, a = (0 - 1)/10
So, a = -0.1 m/s^2
(minus sign indicates that the object is decelerating i.e. its velocity is decreasing)

• Mass of the body (m) = 10 kg

Force (F) = m × a
So, F = 10 × (-0.1)
So, F = -1 N
(Here, minus sign indicates that the force is applied in the opposite direction of the motion of the body)

Hence, force applied is 1 newton.

• According to the second kinematical equation of motion,
v^2 = u^2 + 2as

So, s = (v^2 - u^2) / 2a

So, s = (0 - 1)/(-0.1)

So, s = (-1)/(-0.1)

So, s = 10 m

Therefore the body travels 10 m before coming to rest.

Answer 2

Answer:

Distance (S) = 10m

Explanation:

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