Question

a body of mass 10 kg is moving with a velocity of 1/sec find the magnitude of the force required to stop it in 10 second what do you conlude from the results ​

Answer 1

Answer:

dil ka Darius beh HI hya isq ibahsad naaab HI hya kudh ko muke ri

Answer 2

Answer:

A body of mass that is 10 kg is moving with a velocity of 15 m per second. What force is required to stop it in 3 seconds?

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Let’s review the 4 basic kinematic equations of motion for constant acceleration (this is a lesson – suggest you commit these to memory):

s = ut + ½ at^2 …. (1)

v^2 = u^2 + 2as …. (2)

v = u + at …. (3)

s = (u + v)t/2 …. (4)

where s is distance, u is initial velocity, v is final velocity, a is acceleration and t is time.

In this case, we have u = 15m/s, v = 0, t = 3s and we want to find acceleration, a, so we use equation (3) v = u + at

0 = 15 + 3a so a = -5m/s^2 (the negative meaning deceleration)

Then from F = ma,

F = 10kg(-5m/s^2) = -50N

So the required force is 50N in the direction opposing the initial velocity.