Question

a body of mass 10 kg is moving with a velocity of 1/sec find the magnitude of the force required to stop it in 10 second what do you conlude from the results ​

Answer 1

Given:-

• Initial velocity = 1m/s
• Velocity (v) = 0m/s
• Time(t) = 10 seconds
• Mass(m) = 10kg

To Find:-

• Magnitude of force required to stop it in 10sec.

Solution :-

Acceleration = (final velocity- initial velocity)/10

or,

⇒ a = (v - u)/10

⇒a = (0 - 1)/10

⇒a = - 0.1 m/s²

Here, acceleration comes in negative form, so, we can conclude that object is decelerating. Deceleration of object directly states that velocity of object is decreasing.

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Now,

Given that mass of the object(m) is 10 kg.

⇒ Force = mass × acceleration

⇒ F = m × a

⇒ F = 10 × ( -0.1 )

⇒ F = -1 N

Magnitude force required is 1 newton.

From this negative value of force, we can conclude that the force is applied in the opposite direction of motion of the body.

Answer 2

Answer:

Given :-

• A body of mass is 10 kg is moving with a velocity of 1 m/s and it is stop it in 10 seconds.

To Find :-

• What is the force required to stop it in 10 seconds.

Formula Used :-

❶ To find acceleration,

★ v = u + at ★

where,

• v = Final velocity
• u = Initial velocity
• a = Acceleration
• t = Time

❷ To find force,

✯ F = ma ✯

where,

• F = Force
• m = Mass
• a = Acceleration

Solution :-

❶ First we have to find the acceleration,

Given :-

• v = 0 m/s
• u = 1 m/s
• t = 10 seconds

According to the question by using the formula we get,

⇒ 0 = 1 + a(10)

⇒ 0 = 1 + 10a

⇒ 0 - 1 = 10a

⇒ - 1 ÷ 10 = a

⇒ - 0.1 = a

➠ a = - 0.1 m/s²

Hence, the acceleration is - 0.1 m/s² .

❷ Now we have to find the force,

Given :

• m = 10 kg
• a = - 0.1 m/s²

According to the question by using the formula we get,

↦ F = 10 × (- 0.1)

➦ F = - 1 N

∴ The force required to stop it in 10 seconds is - 1 N .