Question

a body of mass 10 kg is moving with a velocity of 5 m/s attainsvof 35m/s in 5 second find the force applied on body to change its velocity.
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Answer 1

Answer:

For a perfectly elastic collision, coefficient of restitution is e=1.

Let u and v be the velocities of 10 kg and 1 g masses after collision.

Thus, e=

rel. vel. of approach

rel. vel.of separation

=

5−0

v−u

=

5

v−u

But, as e=1, we have v−u=5.

Total momentum before collision is P=10×5=50 kg m/s

Total momentum after collision is P=10×(v−5)+0.001×v=10.001v−50

Thus, 10.001v−50=50⇒v=

10.001

100

≈10 m/s

Hope it will help.