a body of mass 10 kg is moving with velocity of 10 ms-1. A force Acts for 5 seconds to reduce its velocity to 2 ms-1. Find the momentum of body before and after application of the force on it.
Answers
Explanation:
Mass of the body =10 kg
Initial velocity u=4 m/s
Final velocity v=8 m/s
Time t=2s
a) Momentum before force acts p
1
=m×u=10×4=40kg.m/s
b) Momentum after force acts p
2
=m×v=10×8=80kg.m/s
c) Gain in momentum per second =
2
40
=20kg.m/s
d) Acceleration a=
t
v−u
=
2
8−4
=2m/s
2
Force =m×a=10×2=20 N
Given: A body of mass 10 kg is moving with velocity of 10 m/s. A force acts for 5 seconds to reduce its velocity to 2 m/s.
To find: Momentum of body before and after collision
Explanation: Let the mass of the body be m, its initial velocity be u and final velocity be v.
Momentum of a body is the product of its mass and its velocity. It is a vector quantity which has both magnitude and direction.
The formula for momentum is
= Mass * Velocity
= m * v
Initial momentum of the body
= Mass * Initial velocity
= m * u
= 10 * 10
= 100 kg m/s
Final momentum of the body
= Mass * Final velocity
= m * v
= 10 * 2
= 20 kg m/s
Therefore, the momentum of the body before and after the application of force is 100 kg m/s and 20 kg m/s respectively.