Question

 A body of mass 10 kg is moving with velocity of 15 ms−1. force required to stop it in 3 seconds should be?

Answer 1

We know that,

F = m*a

Using 1 eqn of motion

v = u + at

Here, v = 0 m/s, u = 15 m/s, t = 3 sec

Therefore, a = -5 m/s²

Hence, Force required is, F = m*a

= 10*(-5) = -50 N


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