Question

A body of mass 10 kg is placed on a smooth
iniclined plane making an angle of 30° with
the horizontal, the component of the force
of gravity trying to move the body down the
inclined plane is (g = 9.8 m/s2]
(a) 98 N
(b) 49 N
(c) 10 N
(d) 5N​

Answer 1

Answer:

49 N

Explanation:

in this the force mg is act downward. the component of this force that try to move body down is

mgsin30°

so,f=mgsin30°

f= 10×9.8×1/2. (sin30°= 1/2)

then f=49N.

answer is(b).