- A body of mass 10 kg is raised from certain
depth. If work done in raising it by 10 m is 1600 J.
its velocity at this position will be (g = 10 m/s2)
Answers
Answered by
1
Answer:
v=(20×2^1/2)/5
Explanation:
Here,
w=F×D
w=m×a×d
w=m×v×t^-1×d
1600=10×v×t^-1×10
16=v×t^-1
16=d/t×1/t
16=10/t^2
t^2=10/16
t=(5/8)^1/2
t=(5/2^3)^1/2
v=10/(5/2^3)^1/2
v=(20×2^1/2)/5
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Answered by
0
Answer:
v=(20×2^1/2)/5
Explanation:
Here,
w=F×D
w=m×a×d
w=m×v×t^-1×d
1600=10×v×t^-1×10
16=v×t^-1
16=d/t×1/t
16=10/t^2
t^2=10/16
t=(5/8)^1/2
t=(5/2^3)^1/2
v=10/(5/2^3)^1/2
v=(20×2^1/2)/5
plz mark me as brainliest and follow me if you like this
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