Question

A body of mass 10 kg moving at a height of 2 m, with uniform speed of 2 m/s. Its total energy is​

Answer 1

Answer:

216

Explanation:

m = 10kg. h = 2m. v=2m/s

KE = 1/2mv²

KE = 1/2 * 10 * 2²

KE = 1/2 * 40

KE = 20

g = 9.8m/2

PE = mgh

PE = 10 * 9.8 * 2

PE = 98 * 2

PE = 196

TE = 196 + 20 = 216

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Answer 2

The total energy of the body is $216J$.

Explanation:

Given,

Mass of the body, $m = 10 kg$

Height moved, $h= 2m$

Uniform speed, $v = 2m/s$

• Kinetic Energy, $K.E. = \frac{1}{2} mv^{2}$

                                           $= \frac{1}{2} (10)(2)^{2}$

                                           $= 20J$

• Potential Energy, $P.E. = mgh$

                                              $= 10(9.8)(2)$

                                              $= 196J$

• Total Energy $= K.E. + P.E.$

                              $= 20+196$

                              $=216J$

Hence, the total energy is $216J$.