Question

A body of mass 10 kg moving with a velocity of 10 m/sec on a horizontal plane. Then the magnitude of work done by the frictional force if it
comes to rest finally is:
O 500 J
O 750J
O 100 J
o 250 J​

Answer 1

m = 10 kg

v = 10 m/s

Work done = ½mv²

$= > work \: done = \frac{1}{2} \times 10 \times 100$

$= > work \: done \: = 500$

Hence, work done is 500 J

Hope this answer helps you ^_^ !