Question

A body of mass 10 kg moving with a velocity of 5m/s comes to rest in 2 seconds. Find the magnitude of force acting on the body

Answer 1

Explanation:

force=rate of change of momentum

f=(mv-mu)t

f=-25N

negative sign inducate that force applied opposite direction of motion

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Answer 2

Explanation:

Mass=10kg

Initial velocity=5m/s

Final velocity=0

Time taken =2sec

acceleration=v-u/t

a=0-5/2

a=-5/2

F=ma

F=10×-5/2

F=-25N Ans