Question

A body of mass 10 kg moving with velocity 20 m/s comes to rest in 10 seconds when a force is applied on it what is the force applied. *
1 punt
-20N
40N
200N
NON​

Answer 1

Answer:

f = ma

= 10×20

=200N

Explanation:

hope that's a right answer

Answer 2

• F = ma ; a = v/t = 20/10 = 2 m/sec^2 ; m = 10kg

so, F = 10 ×2 = 20 N

• The answer is: 20N