Question

 A body of mass 10 kg moving with velocity 20 m/s comes to rest in 10 seconds when a force is applied on it what is the force applied. *
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Answer 1

Answer:

20N force applied on it.

Explanation:

Given that,

• Mass (m) = 10kg
• Initial velocity (u) = 0m/s
• Final velocity (v) = 20m/s
• Time (t) = 10 s

Applying 1st equation of motion,

✒ v = u + at

[ Where, v = final velocity, u = initial velocity, a = acceleration, t = time ]

➡ 20 = 0 + a × 10

➡ 20 = 10a

➡ a = 20/10

➡ a = 2 m/s²

As we know that,

✒ F = ma

[ Where, F = force, m = mass, a = acceleration ]

➡ F = 10 × 2

➡ F = 20N

Answer 2

Here, we are asked to find the force applied, so let us do it with the help of the appropriate (suitable) formula used :

GIVEN :

• Body of Mass = 10kg
• Inital Velocity = 0 m/s
• Final Velocity gained = 20 m/s
• Time taken = 10 seconds

TO FIND :

• Force applied on it = ?

STEP - BY - STEP EXPLAINATION :

Now, as per the given question we are given here are some of the important terms and using those important terms we will have to solve the question, so let us start it :

We will have to use the appropriate formula –

• v = u + at

When we will separate the values and write it into simpler form, we will get here as :

Final velocity = initial velocity + ( Acceleration × Time ) [at]

[ substituting the values as per the formula ]

⟼ v = u + at

⟼ 20 = 0 + a × 10

⟼ 20 = 10a

⟼ a = 20/10 = 2

⟼ a = 2m/s²

Therefore, the value we gained = 2m/s²

━━━━━━━━━━━━━━━━━━━━━━━━━

Now, as per the provided question we have to find force applied, therefore we will use the appropriate formula to find it :

Formula used for Force –

• F = ma

[When separated]

• Force = mass × acceleration

[ substituting the values as per the formula ]

⟼ F = ma

(considering here Force as 'F' for solving)

⟼ F = 10 × 2 = 20

⟼ F = 20N (20 Newton)

Hence, the appropriate answer = 20Newton ✓