Question

a body of mass 10 kg rests on a horizontal plane the co-efficient of friction between the body and plane is 0.15. find the work done in moving the body through a distance of 10 metres​

Answer 1

munna answer 150joule hai

Answer 2

Step-by-step explanation:

m=10kg

u= 0.15

s= 10m

F=uN

u= coefficient of friction , N = normal force

N= mg where g is accelerate due to gravity =10m/s^2

N = 10kg × 10m/s^2=100N

frictional force = 0.15×100= 15u

s=10m , angle=0

w= f×s costheta

w= 15×10

w= 150uKJ