Question

a body of mass 10 kg started from rest covers 10 m in 2 sec . calculate the work done in moving the body​

Answer 1

Explanation:

mass = 10kg

S = displacement = 10m

time = 2sec

S = ut+1/2 at^2

If starts from rest [therefore u = 0]

10 = 1/2 a(4)

a = 5 m/s^2

Force = m×a

= 10 × 5

= 50 N

Work done = Force × Displacement

= 50 × 10

= 500

Answer 2

Answer: 500

Explanation:

s = 10m

m = 10kg

t = 2sec

work done = ?

solution = s = ut+1/2*at^2

= 10 = 0+1/2*a*4

= a = 10/2

a=5 m/s^2

force = mass * acceleration

        = 10 * 5

         = 50 N

work done = force * disp.

                 = 50 * 10          

                  = 500