Question

a body of mass 10 kg starting from rest ,accelerates uniformly to a speed of 30m/s in 10 s. Brakes are applied on the body stops in next 5 sec. calculate the accelerating force and the stopping force​

Answer 1

Answer:

Given,

m=10kg

u=30m/s

v=0m/s

t=5sec

As we know Force=mass×acceleration

& secondly acceleration=v-u/t. So,

F=10kg×0-30/5

F=10×6

Then,F=60N

Answer 2

The accelerating force and the stopping force​ are 30 N and (-60 N) respectively.

Explanation:

Given that,

Mass of the body, m = 10 kg

Initial speed, u = 0

Final speed, v = 30 m/s

Time, t = 10 s

In this case, the accelerating force is given by :

$F=ma\\\\F=m\dfrac{v-u}{t}\\\\F=10\times \dfrac{30-0}{10}\\\\F=30\ N$

Second case,

Initial speed, u = 30 m/s

Brakes area applied, v = 0

Time t = 5 s

$F=ma\\\\F=m\dfrac{v-u}{t}\\\\F=10\times \dfrac{0-30}{5}\\\\F=-60\ N$

Hence, the accelerating force and the stopping force​ are 30 N and (-60 N) respectively.

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