A body of mass 10 kg starting from rest accelerates uniformly to a speed of 30
m/s in 10 s. Breaks is applied and the body stops in next 5 seconds. (1×4=4)
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Answer:
Given,
Mass (m) = 10 kg
Initial Velocity (u) = 0 m/s
Final Velocity (v) = 30 m/s
Time (t) = 10 s
1. Acceleration = v-u/t
= 30/10 m/s²
= 3 m/s²
Accelerating force = ma
= 10*3 N
= 30 N (Option A)
2. Initial Velocity (u) = 30 m/s
Time (t) = 5 s
Final Velocity (u) = 0 m/s
Retardation = u-v/t
= 30/5 m/s²
= 6 m/s²
Retarding force = ma
= 10*6 N
= 60 N (Option A)
3. Ratio of Acceleration to Retardation = 30:60
= 1:2 (Option B)
I hope this helps.
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