Question

a body of mass 10 kg starting from rest accelerats uniformly to a speed metre per second brakes are applied and the body stops in next 5 seconds. the retarding force on the body is​

Answer 1

Answer:

A car of mass 480 kg moving at a speed of 15m/s is stopped by applying brakes in 10s. Calculate the force applied by the brakes.

Step-by-step explanation:

720 N

given that,

A car of mass 480 kg moving at a speed of 15m/s

here,

mass of car = 480 kg

initial velocity of car = 15 m/s

and

also given that,

the car stopped by applying brakes in 10s.

so,

final velocity = 0

time to stop car by brakes = 10 seconds

now,

we have

final velocity(v) = 0

initial velocity(u) = 15 m/s

time(t) = 10 seconds

acceleration(a) = (v - u)/t

putting the values,

a = (0 - 15)/10

a = -15/10

a = -1.5 m/s²

negation of the acceleration shows the retardation

now,

by the newtons 2nd law of motion

F = Ma

where,

F = force

M = mass

a = acceleration

given,

mass of the car = 480 kg

acceleration = -1.5 m/s²

putting the values,

F = Ma

F = 480(-1.5)

F = -720 N

negation of the Force shows the motion of the body opposite the force

so,

force applied by brakes to stop the car moving with the velocity 15 m/s in 10 seconds = 720 N

Answer 2

Answer:

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Step-by-step explanation:

A body of mass 10kg starting from rest, accelerates uniformly to a speed of 30m//s in 10s. Brakes are applied and the body stops in next 5 seconds, (figure). Calculate the accelerating force and the stopping force. ∴ Retarding force F=ma=10(-6)=-60N.