Question

A body of mass 100 g is at rest on a smooth surface . A force of 0.1 N acts. on it for 5sec .Calculate the distance traveled by the body​
plz answer fast​

Answer 1

Mark as brainliest for the answer.....

m = 100/ 1000 kg

= 0.1 kg

F = 0.1 N

u = 0 m/s

t = 5 sec

s = ?

F = ma

0.1 = 0.1 × a

a = 1

$s = ut + \frac{1}{2} a {t}^{2}$

s = 0 + 1/2 × 1 × 5 × 5

s = 25/2

s = 12.5 m

Mark as brainliest and follow

Answer 2

Answer:

Hope it helps you... Distance = 12.5 m