A body of mass 100 g is at rest on a smooth surface . A force of 0.02 N acts. on it for 5sec .Calculate the distance traveled by the body?
Answers
Answered by
1
m=0.1kg
F=0.02N
t=5s
F=ma
0.02=0.1×a
0.02/0.1=a
a=0.2m/s
so as it's at rest so u=0
s=ut+½at^2
s=0×5+½×0.2×25
s=0.1×25
s=2.5m
this is the distance covered
please mark my hard work as brainlist
F=0.02N
t=5s
F=ma
0.02=0.1×a
0.02/0.1=a
a=0.2m/s
so as it's at rest so u=0
s=ut+½at^2
s=0×5+½×0.2×25
s=0.1×25
s=2.5m
this is the distance covered
please mark my hard work as brainlist
akankshadilipadhav:
ok
please brainlist it
yes
wait for few minutes
Similar questions