Question

A body of mass 100 g is projected vertically upwards with an initial velocity of 49m/s find i) force of gravity on the body ii) magnitude and direction of acceleration of the body iii) vertical height attained by the body iv) total time of flight

Answer 1

i) F = ma

m = 100/1000 = 0.1 kg

a = -g = -9.8m/s²

F = ma = 0.1×-9.8 = -0.98N

ii) Magnitude of acceleration = 9.8m/s²

Direction of acceleration = vertically downwards

iii) v² = u²+2as

0 = u²-2gh

2gh = u²

h = u²/2g = 49×49/2×9.8 = 122.5m

iv) v = u+at

0 = 49-9.8t

t = 49/9.8 = 5s

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