a body of mass 100 gram is at rest on the smooth surface of force of 0.2 Newton acts on it for 5 seconds calculate the distance travelled by the body
Answers
Explanation:
mass (m) = 100 g = 0.1 kg
force (f) = 0.2 Newton
time taken (t) = 5 seconds
initial velocity (u) = 0
to find : distance travelled by the body (s)
solution :
force = mass × acceleration
0.2 = 0.1×a
a = 2 m/s^2
by using 2nd equation of motion
s = ut+1/2at^2
s = 0+1/2*2*(5)^2
s = 25 meter
So, the body will travel a distance of 25 meter.
Given :-
Mass of a body = 100 grams
Force applied on the body when it is at rest = 0.2 Newton
To find :- Distance travelled in 5 seconds
Solution :-
Mass of a body = 100 grams
Force applied on the body when it is at rest = 0.2 Newton
Find acceleration of the body
To find it first see that mass and force are of same unit systems
Here Force - SI
Mass - MKS
So, we will convert Mass units from MKS to SI
SI unit of Mass = Kg
So we need to convert g to Kg
We know that. 1 Kg = 1000 g
So, 1g = 1/1000 Kg
Mass in( SI unit system) = 100 * 1/1000 = 100/1000 = 1/10 Kg
Mass = 1/10 Kg
So, Acceleration = 2 m/s²
From above we get information as,
Acceleration(a) = 2 m/s²
Given body started from rest
Initial velocity (u) = 0 m/s
Time(t) = 5 seconds
Distance (s) = ?
These all values are in second equation of motion i.e, s = ut + 1/2 at²
By substituting the values in the equation,