Question

A body of mass 100 kg is at a distance equal to the radius of earth R, from the surface of the earth. The
gravitational force experienced by the earth due to the body is 2 * Y newton, where Y is
(Given : Radius of Earth, R = 6400 km; Acceleration due to gravity at Earth's surface, g = 10 m/s2)​

Answer 1

Given : A body of mass 100 kg is at a distance equal to the radius of earth R, from the surface of the earth. The

gravitational force experienced by the earth due to the body is 2 * Y newton,

Radius of Earth, R = 6400 km; Acceleration due to gravity at Earth's surface, g = 10 m/s2)​

To Find : Y

Solution:

F  = G Mm/(R+100)²

F =  GMm/R²(1+100/R)²

GM/R²  = g

F = mg/(1+100/R)²

m = 100 kg

g  =  10 m /s²

R = 6400 km

=> F = 100 * 10 / ( 1 + 100/6400)²

=> F = 1000 / 1.0315

=> F = 969.46  N

2 * Y  = 969.46 N

=> Y = 484.73

Y = 484.73

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Answer 2

Answer:

F=G.m1.m2/R2

here , M1=mass of earth

M2=mass of body(i.e. 100kg)

R=height of object from centre of earth i.e. 2R

now formula will be

F=G.M.100/4R2. (1)

now,

g=GM/R2

so, G.M=g.R2

substituting in (1)

so, F=g.R2.100/4R2. (here g=10)

so, F=10.100/4=2*Y

so, Y=125