A body of mass 100 kg is at a distance equal to the radius of earth R
from the surface of the earth. The gravitational force experienced by
the earth due to the body is 2 * Y newton, where Y is
(Given : Radius of Earth, R = 6400 km; Acceleration due to gravity at
Earth's surface, g = 10 m/s)
Enter Your Answer
Answers
Answered by
2
Explanation:
Answer:
According to Universal law of gravitation, the force of attraction between 2 bodies is:-
F = (G m1m2)/r2
Where m1m2 = the masses of the two bodies,
r = distance between them
G = gravitational Constant
When the distance is reduced to half i.e. r’ = (1/2) r then,
F’ = (G m1m2)/r2
= (G m1m2)/(r/2)2
= (4 G m1m2)/ (r2) = 4F
Therefore when the distance between the objects is reduced to half, then the force of gravitation increases by four times the original force.
Similar questions