a body of mass 100 kg is moving with a velocity of 20 m/s it is brought to rest by the force of friction due to ground in 10 second .calculate the retarding force assuming uniform retardation
Answers
Answered by
1
200 newton is the retarding force
genius9:
ples mark as brainliest
Answered by
4
Given ;
m = 100 kg
u = 20m/s
v = 0
t = 10 sec
v = u+at
0 = 20+10a
a = -2 m/s^2
Force
= ma
= 100×-2
= -200 N
hence the retarding force will be 200N in the opposite direction of the motion.
m = 100 kg
u = 20m/s
v = 0
t = 10 sec
v = u+at
0 = 20+10a
a = -2 m/s^2
Force
= ma
= 100×-2
= -200 N
hence the retarding force will be 200N in the opposite direction of the motion.
Similar questions