A body of mass 100 kg stands on a spring weighing machine inside a lift. The lift starts to
ascend with acceleration of 2.2 m s-2. What is the reading of the machine?
Answers
QuestioN :
A body of mass 100 kg stands on a spring weighing machine inside a lift. The lift starts to ascend with acceleration of 2.2 m s-2. What is the reading of the machine?
GiveN :
- Mass ,m = 100 kg
- Acceleration ,a = 2.2 m/s²
To FiNd :
- Reading of the Machine.
ANswer :
The reading of the Machine is 122.44 kg.
SolutioN :
As we have to calculate the weight reading by the machine.
As we know that the acceleration due to gravity (g) is 9.8m/s². The ball is falling down on the earth's surface.
Therefore, the combined acceleration
• a' = a + g.
where,
- g denote acceleration due to gravity
- a denote ascend with acceleration.
→ a' = 2.2 + 9.8
→ a' = 12 m/s²
Hence, the combined acceleration is 12m/s²
Now, calculating the reading of spring
→ Reading of Machine = m × a'/g
→ Reading of Machine = 100×12/9.8
→ Reading of Machine = 1200/9.8
→ Reading of Machine = 122.44 kg
∴Hence, the reading of Machine is 122.44 kg.
Answer:
122.44 kg.
Step-by-step explanation:
→ a' = 2.2 + 9.8
→ a' = 12 m/s²
Hence, the combined acceleration is 12m/s²
Now, calculating the reading of spring
→ Reading of Machine = m × a'/g
→ Reading of Machine = 100×12/9.8
→ Reading of Machine = 1200/9.8
→ Reading of Machine = 122.44 kg
∴Hence, the reading of Machine is 122.44 kg.