a body of mass 1000kg moving at a speed of 10m/s reaches the speed of 50m/s in 20s calculate the force required to do so
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Answered by
78
mass m =1000kg
initial velocity u =10m/s
final velocity V =50m/s
time t =20s
force F =rate of change of momentum
F=m(v-u)/t
F=1000(50-10)/20
F=1000x40/20
F=2000N.
initial velocity u =10m/s
final velocity V =50m/s
time t =20s
force F =rate of change of momentum
F=m(v-u)/t
F=1000(50-10)/20
F=1000x40/20
F=2000N.
mawbleiwelldone:
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Answered by
37
given.,
mass = 1000kg
initial velocity ( u ) = 10m/s
final velocity ( v ) = 50m/s
time = 20s
acceleration = v-u/t
a = 50-10 / 20
a = 40/20
a = 2 m/s^2
force = mass×acceleration
f = 1000 × 2
f =2000N
hope it will help uh...
mass = 1000kg
initial velocity ( u ) = 10m/s
final velocity ( v ) = 50m/s
time = 20s
acceleration = v-u/t
a = 50-10 / 20
a = 40/20
a = 2 m/s^2
force = mass×acceleration
f = 1000 × 2
f =2000N
hope it will help uh...
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