Question

a body of mass 100g is at rest on a smooth surface. a force of 0.2 acts on its for 5 sec . calculate the distance travelled by the body.​

Answer 1

Answer:

m=100g=100/1000=0.100

u=0

t=5 secs

s=?

F=ma

0.2=0.1×a

a=20 m/s^2

s=ut + 1/2(at)^2

=0+1/2×20×20×5×5

=10×20×25

=200×25

=5,000m

therefore, s=5,000 m