Question

a body of mass 100g is at rest on a smooth surface.A force of 0.2 N acts on it for 3 seconds then the distance travelled by the body is

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Answer 1

Mass = 100g = 0.1kg

Force = 0.2N

F = ma

a = F/m = 0.2/0.1 = 2m/s²

We know that,

u = 0m/s (Mass was at rest initially)

S = ?

t = 3s

a = 2m/s²

Hence we can use the equation,

S = ut + ½at²

= 0 + ½ × 2 × 3² = 9m

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Answer 2

Answer:

9 m

Explanation:

mass=100g=100×10^-3kg=100/1000=1/10=0.1kg

Force =m×a

>a=F/m

>a=0.2/0.1

=1 s/t^2

a= v/t

>v=a×t

>v=1×3=3 s/t

again v=s/t

>s=v×t=3×3=9m

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