Question

a body of mass 100g is at rest on a smooth surface . a force of 0.2 newton acts on it for 5 secs . calculate the distance travelled by the body .

Answer 1

here is your answer

given :

mass (m) = 100 g = 0.1 kg

force (f) = 0.2 Newton

time taken (t) = 5 seconds

initial velocity (u) = 0

to find : distance travelled by the body (s)

solution :

force = mass×acceleration

0.2 = 0.1×a

a = 2 m/s^2

by using 2nd equation of motion

s = ut+1/2at^2

s = 0+1/2*2*(5)^2

s = 25 meter

so, the body will travel a distance of 25 meter.