A body of mass 100g is sliding on an inclined
plane with an inclination of 60°. What is the
frictional force experienced, if coefficient of friction
is 1.7 ? (take g = 10 m/s2)
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Answered by
5
Answer:
8500 N
Explanation:
We know that
Body of mass m = 100 g
Plane of the inclination is Ф = 60 degree
Coefficient of friction is μ = 1.7
g = 10 m/s²
Now ,
We know that,
Normal force f = mg cosФ
So
f = 100 × 10 × cos 60
f = 5000 N
Now
Frictional Force = Coefficient of friction × normal force
F = μ f
F = 1.7 × 5000
Frictional force is F = 850 N
Correct answer is 850 N
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