Question

a body of mass 100g moving the velocity 12m/s . is stoped by a applying a force of 0.6N . calculate the time taken to stop the body also calculate the impulse of this force​

Answer 1

Answer:

f=ma

m=100/1000=0.1

dv=12

f=0.6N

0.6=0.1*12/dt

0.6=1.2/dt

dt=2sec

impluse =force *time interval

I=f*t

I=0.6*2=1.2NS

Answer 2

Answer:

m=100/1000 kaise hua plz explain