A body of mass 100g moving with an initial velocity of 4m/s collides with another body of mass 150g moving in opposite direction with velocity 6m/s. If the collision is perfectly inelastic, after collision the velocity is
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3
after collision both will stick together and move with the common velocity which is given by M1U1 plus M2U2 is equals to (M1 plus M2) x v
Where v is common velocity.
Where v is common velocity.
Answered by
3
MaVa+MbVb=MaUa+MbUb
Ma=100g
Ua=4m/s
Mb=150g
Ub=6m/s
in the question it is given that both are in opposite direction
so the velocity is zero
Ma=100g
Ua=4m/s
Mb=150g
Ub=6m/s
in the question it is given that both are in opposite direction
so the velocity is zero
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