a body of mass 100g starts from rest and acquires the steady velocity due to a force of 1000 N for 0.01 second and final velocity
Answers
Given:-
- Mass of Body = 100g = 0.1kg
- Initial Velocity = 0m/s (As it was in rest).
- Force exerted = 1000N.
- Time given = 0.01s
To Find:-
- Final Velocity of the Body.
FORMULAE USED
- v = u + at
- F = ma
Where,
v = Final Velocity
u = Initial Velocity
a = Acceleration
t = time
F = Force
m = Mass
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Now, First we will find Acceleration
F = ma
1000 = 0.1 × a
a = 1000/0.1
a = 10000m/s²
Hence, The Acceleration produced is 10000m/s².
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Therefore,
v = u + at
v = 0 + 10000 × 0.01
v = 100m/s
Hence, The Final Velocity acquired by body is 100m/s.
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Explanation:
Given that, a body of mass 100g or 0.1 kg starts from rest and acquires the steady velocity due to a force of 1000 N for 0.01 second.
We have to find the final velocity of the body.
Force is defined as the product of mass and acceleration.
Force = Mass × Acceleration
→ 1000 = 0.1 × a
→ 1000/0.1 = a
→ 10000 = a
Therefore, the acceleration of the body is 10000 m/s².
Now,
Using the first equation of motion,
v = u + at
Substitute the known values,
→ v = 0 + 10000(0.01) [as body starts from rest so the initial velocity is 0 m/s]
→ v = 0 + 100
→ v = 100
Hence, the final velocity of the body is 100 m/s.