Question

A body of Mass 100gis at rest on smooth surface. A force of 0.1N act on it for 5 second . calculate the distance traveled by the body

Answer 1

100g we need to convert to kg

100g = 0.1 kg


We know that,

Force = mass × acceleration

=> 0.1 = 0.1 × acceleration

=> acceleration = 0.1/0.1

=> acceleration = 1 m/s²

Now, we know the body was at rest

so its initial velocity u will be 0

time given 5 second

and acceleration we have find out as 1

We know that

s (displacement) = ut + 1/2at²

So substituting the value we get,

s = 0 × 5 + 1/2 × 1 × (5)²

=> s = 1/2. × 25

=> s = 25/2

=> s = 12.5 m


So the body covered a distance of 12.5 m


Hope it helps dear friend ☺️✌️