A body of Mass 10kg is acted upon by a constant force of 30Ñ for 2sec.Calculate the kinet energy gained by the body.
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Answered by
4
Answer:
give
Explanation:
Given:-
m=10 kg
F=30N
t=2 sec
therfore, F=m×a
a=F/m
=30/10
=3 m/s^2
as we know,
a=v/t
v=a×t
=3×2
=6m/s
.•.K.E=1/2mv^2
=1/2×10×(6)^2
=1/2×10×36
=180 J
Answered by
4
Answer:
The answer is 180 J
Explanation:
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