Question

A body of mass 10kg is acted upon by two forces each of magnitude 10N making an angle of 60° with each other . Find the net acceleration of the body in m/s^2.

Answer 1

Net acceleration of the body is 1.732 m/s^2

The resultant of the forces acted on the body is calculated as

R=√(p^2+q^2+2pqcosθ)

R=$\sqrt{10^2+10^2+2*10*10*cos60}$

R=17.32 N

The net acceleration on the body is calculated by the D'Alembert's principal

R=ma

17.32=10*a

a=1.732 m/s^2

Answer 2

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