A body of mass 10kg is dropped from a point where it possess on energy 100 j . then the KE when it reaches ground would be
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Initial total energy = 100 J
Final total energy = ?
According to law of conservation of energy
Initial total energy of body = Final Total energy of body
So, Final Total energy = 100 J
When the ball hits the ground the only energy it possses is kinetic energy.
∴ Total initial energy (= 100 J) is converted into kinetic energy
In other words, kinetic energy when it hits the ground is 100 J
In case if you want velocity with which it hits the ground then,
K.E = 0.5mv²
v = √(2K.Em)
= √(2 × 100 J × 10 kg)
= 20√(5) m/s
It hits the ground with velocity equal to 20√(5) m/s
Final total energy = ?
According to law of conservation of energy
Initial total energy of body = Final Total energy of body
So, Final Total energy = 100 J
When the ball hits the ground the only energy it possses is kinetic energy.
∴ Total initial energy (= 100 J) is converted into kinetic energy
In other words, kinetic energy when it hits the ground is 100 J
In case if you want velocity with which it hits the ground then,
K.E = 0.5mv²
v = √(2K.Em)
= √(2 × 100 J × 10 kg)
= 20√(5) m/s
It hits the ground with velocity equal to 20√(5) m/s
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