A body of mass 10kg is moving whith velocity 10 m/s.the work done to stop the body is
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Hey buddy your answer
Explanation:
The kinetic energy of a body of mass m=10kg moving at v=10m/s is
E=(1/2)mv²
After being stopped, the kinetic energy of the body has been transferred to work done (assuming no frictional loss), and has nothing left.
So we can find
Work done=loss/reduction in kinetic energy.
E=1/2*10*10*10=500 J
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