Physics, asked by rushghadge7716, 1 year ago

A body of mass 10kg is moving with a constant velocity of 10 m\s when a constant force act for 4sec on it moves with a velocity 2 m\s in the opposite direction the acceleration produced in it is

Answers

Answered by Mehreen29
4
u= 10m/s
v= -2m/s
t= 4 sec
a=v-u/t
a= -2-10/4=-12/4=-3m/s²
Therefore a= -3m/s²
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